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43372044413 is a prime number
BaseRepresentation
bin101000011001001011…
…001110000001111101
311010221200011010211022
4220121023032001331
51202311220410123
631531433233525
73063541203035
oct503113160175
9133850133738
1043372044413
111743742aa05
1284a52628a5
13412286ab09
14215637c8c5
1511dca6b1c8
hexa192ce07d

43372044413 has 2 divisors, whose sum is σ = 43372044414. Its totient is φ = 43372044412.

The previous prime is 43372044409. The next prime is 43372044437. The reversal of 43372044413 is 31444027334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40787033764 + 2585010649 = 201958^2 + 50843^2 .

It is a cyclic number.

It is not a de Polignac number, because 43372044413 - 22 = 43372044409 is a prime.

It is a super-2 number, since 2×433720444132 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43372044713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21686022206 + 21686022207.

It is an arithmetic number, because the mean of its divisors is an integer number (21686022207).

Almost surely, 243372044413 is an apocalyptic number.

It is an amenable number.

43372044413 is a deficient number, since it is larger than the sum of its proper divisors (1).

43372044413 is an equidigital number, since it uses as much as digits as its factorization.

43372044413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 35.

The spelling of 43372044413 in words is "forty-three billion, three hundred seventy-two million, forty-four thousand, four hundred thirteen".