4340131319 has 2 divisors, whose sum is σ = 4340131320. Its totient is φ = 4340131318.

The previous prime is 4340131253. The next prime is 4340131321. The reversal of 4340131319 is 9131310434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4340131319 - 2⁸ = 4340131063 is a prime.

It is a super-2 number, since 2×4340131319² = 37673479732329359522, which contains 22 as substring.

Together with 4340131321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4340131291 and 4340131300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4340131919) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2170065659 + 2170065660.

It is an arithmetic number, because the mean of its divisors is an integer number (2170065660).

Almost surely, 2^4340131319 is an apocalyptic number.

4340131319 is a deficient number, since it is larger than the sum of its proper divisors (1).

4340131319 is an equidigital number, since it uses as much as digits as its factorization.

4340131319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The square root of 4340131319 is about 65879.6730334934. The cubic root of 4340131319 is about 1631.1765025453.

The spelling of 4340131319 in words is "four billion, three hundred forty million, one hundred thirty-one thousand, three hundred nineteen".