4340140120433 has 4 divisors (see below), whose sum is σ = 4673997052788. Its totient is φ = 4006283188080.

The previous prime is 4340140120409. The next prime is 4340140120483. The reversal of 4340140120433 is 3340210410434.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 280209305104 + 4059930815329 = 529348^2 + 2014927^2 .

It is a cyclic number.

It is not a de Polignac number, because 4340140120433 - 2⁶ = 4340140120369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4340140120396 and 4340140120405.

It is not an unprimeable number, because it can be changed into a prime (4340140120483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166928466158 + ... + 166928466183.

It is an arithmetic number, because the mean of its divisors is an integer number (1168499263197).

Almost surely, 2^{4340140120433} is an apocalyptic number.

It is an amenable number.

4340140120433 is a deficient number, since it is larger than the sum of its proper divisors (333856932355).

4340140120433 is a wasteful number, since it uses less digits than its factorization.

4340140120433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 333856932354.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4340140120433 its reverse (3340210410434), we get a palindrome (7680350530867).

The spelling of 4340140120433 in words is "four trillion, three hundred forty billion, one hundred forty million, one hundred twenty thousand, four hundred thirty-three".