Base | Representation |
---|---|
bin | 111111001010001111100… |
… | …010011101011100100011 |
3 | 120100221010201111022101021 |
4 | 333022033202131130203 |
5 | 1032102441214104410 |
6 | 13121530130550311 |
7 | 625402206002134 |
oct | 77121742353443 |
9 | 16327121438337 |
10 | 4340325144355 |
11 | 14237a3434752 |
12 | 5a1226138397 |
13 | 2563a216c4b5 |
14 | 110103cc9c8b |
15 | 77d7d979eda |
hex | 3f28f89d723 |
4340325144355 has 16 divisors (see below), whose sum is σ = 5454183034944. Its totient is φ = 3309472714240.
The previous prime is 4340325144349. The next prime is 4340325144361. The reversal of 4340325144355 is 5534415230434.
It is an interprime number because it is at equal distance from previous prime (4340325144349) and next prime (4340325144361).
It is not a de Polignac number, because 4340325144355 - 213 = 4340325136163 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 67124194 + ... + 67188823.
It is an arithmetic number, because the mean of its divisors is an integer number (340886439684).
Almost surely, 24340325144355 is an apocalyptic number.
4340325144355 is a deficient number, since it is larger than the sum of its proper divisors (1113857890589).
4340325144355 is a wasteful number, since it uses less digits than its factorization.
4340325144355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134313326.
The product of its (nonzero) digits is 1728000, while the sum is 43.
The spelling of 4340325144355 in words is "four trillion, three hundred forty billion, three hundred twenty-five million, one hundred forty-four thousand, three hundred fifty-five".
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