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43405013231 is a prime number
BaseRepresentation
bin101000011011001000…
…111111000011101111
311011000222012010112122
4220123020333003233
51202343140410411
631535012023155
73064421345036
oct503310770357
9134028163478
1043405013231
1117453aa8968
1284b4301abb
1341296421a8
14215a8c171d
1511e08ce9db
hexa1b23f0ef

43405013231 has 2 divisors, whose sum is σ = 43405013232. Its totient is φ = 43405013230.

The previous prime is 43405013221. The next prime is 43405013233. The reversal of 43405013231 is 13231050434.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 43405013231 - 26 = 43405013167 is a prime.

It is a super-2 number, since 2×434050132312 (a number of 22 digits) contains 22 as substring.

Together with 43405013233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 43405013231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43405013233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21702506615 + 21702506616.

It is an arithmetic number, because the mean of its divisors is an integer number (21702506616).

Almost surely, 243405013231 is an apocalyptic number.

43405013231 is a deficient number, since it is larger than the sum of its proper divisors (1).

43405013231 is an equidigital number, since it uses as much as digits as its factorization.

43405013231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 43405013231 its reverse (13231050434), we get a palindrome (56636063665).

The spelling of 43405013231 in words is "forty-three billion, four hundred five million, thirteen thousand, two hundred thirty-one".