43412121142021 has 4 divisors (see below), whose sum is σ = 45696969623200. Its totient is φ = 41127272660844.

The previous prime is 43412121141971. The next prime is 43412121142079. The reversal of 43412121142021 is 12024112121434.

43412121142021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 43412121142021 - 2¹¹ = 43412121139973 is a prime.

It is a super-2 number, since 2×43412121142021² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43412121142421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1142424240561 + ... + 1142424240598.

It is an arithmetic number, because the mean of its divisors is an integer number (11424242405800).

Almost surely, 2^{43412121142021} is an apocalyptic number.

It is an amenable number.

43412121142021 is a deficient number, since it is larger than the sum of its proper divisors (2284848481179).

43412121142021 is a wasteful number, since it uses less digits than its factorization.

43412121142021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2284848481178.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 43412121142021 its reverse (12024112121434), we get a palindrome (55436233263455).

The spelling of 43412121142021 in words is "forty-three trillion, four hundred twelve billion, one hundred twenty-one million, one hundred forty-two thousand, twenty-one".