Base | Representation |
---|---|
bin | 10011101111011101011001… |
… | …01010100110100111000100 |
3 | 12200201011022001222001120221 |
4 | 21313232230222212213010 |
5 | 21142231021103410040 |
6 | 232155131404034124 |
7 | 12100265040453454 |
oct | 1167565452464704 |
9 | 180634261861527 |
10 | 43412131310020 |
11 | 12917a884109a0 |
12 | 4a5168ab32944 |
13 | 1b2b991b54345 |
14 | aa12307b3d64 |
15 | 5043b0db674a |
hex | 277bacaa69c4 |
43412131310020 has 24 divisors (see below), whose sum is σ = 99453246274368. Its totient is φ = 15786229567200.
The previous prime is 43412131309999. The next prime is 43412131310071. The reversal of 43412131310020 is 2001313121434.
It is a super-2 number, since 2×434121313100202 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98663934576 + ... + 98663935015.
It is an arithmetic number, because the mean of its divisors is an integer number (4143885261432).
Almost surely, 243412131310020 is an apocalyptic number.
It is an amenable number.
43412131310020 is an abundant number, since it is smaller than the sum of its proper divisors (56041114964348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43412131310020 is a wasteful number, since it uses less digits than its factorization.
43412131310020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197327869611 (or 197327869609 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 43412131310020 its reverse (2001313121434), we get a palindrome (45413444431454).
The spelling of 43412131310020 in words is "forty-three trillion, four hundred twelve billion, one hundred thirty-one million, three hundred ten thousand, twenty".
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