Base | Representation |
---|---|
bin | 1100101000101000010… |
… | …10101001110101100101 |
3 | 1112111120021020201221221 |
4 | 12110110022221311211 |
5 | 24103044242042041 |
6 | 531234145140341 |
7 | 43236101255245 |
oct | 6242412516545 |
9 | 1474507221857 |
10 | 434130034021 |
11 | 1581280a5092 |
12 | 7017932a6b1 |
13 | 31c27552c48 |
14 | 17024d2db25 |
15 | b45cdd12d1 |
hex | 65142a9d65 |
434130034021 has 4 divisors (see below), whose sum is σ = 456978983200. Its totient is φ = 411281084844.
The previous prime is 434130034007. The next prime is 434130034027. The reversal of 434130034021 is 120430031434.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 434130034021 - 217 = 434129902949 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (434130034027) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11424474561 + ... + 11424474598.
It is an arithmetic number, because the mean of its divisors is an integer number (114244745800).
Almost surely, 2434130034021 is an apocalyptic number.
It is an amenable number.
434130034021 is a deficient number, since it is larger than the sum of its proper divisors (22848949179).
434130034021 is a wasteful number, since it uses less digits than its factorization.
434130034021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22848949178.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 434130034021 its reverse (120430031434), we get a palindrome (554560065455).
The spelling of 434130034021 in words is "four hundred thirty-four billion, one hundred thirty million, thirty-four thousand, twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •