Base | Representation |
---|---|
bin | 10011101111100000111001… |
… | …10100101011100101001101 |
3 | 12200201100011012200210222220 |
4 | 21313300130310223211031 |
5 | 21142243344312000023 |
6 | 232200042223125553 |
7 | 12100362466533225 |
oct | 1167603464534515 |
9 | 180640135623886 |
10 | 43414013000013 |
11 | 129188635a0497 |
12 | 4a51b151438b9 |
13 | 1b2bc01946a86 |
14 | aa136c673085 |
15 | 5044711a93e3 |
hex | 277c1cd2b94d |
43414013000013 has 8 divisors (see below), whose sum is σ = 61290371294208. Its totient is φ = 27240165019584.
The previous prime is 43414013000009. The next prime is 43414013000063. The reversal of 43414013000013 is 31000031041434.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 43414013000013 - 22 = 43414013000009 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43414013000063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 425627578381 + ... + 425627578482.
It is an arithmetic number, because the mean of its divisors is an integer number (7661296411776).
Almost surely, 243414013000013 is an apocalyptic number.
It is an amenable number.
43414013000013 is a deficient number, since it is larger than the sum of its proper divisors (17876358294195).
43414013000013 is a wasteful number, since it uses less digits than its factorization.
43414013000013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 851255156883.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 43414013000013 its reverse (31000031041434), we get a palindrome (74414044041447).
The spelling of 43414013000013 in words is "forty-three trillion, four hundred fourteen billion, thirteen million, thirteen", and thus it is an aban number.
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