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434201402113 = 23184710221073
BaseRepresentation
bin1100101000110000110…
…10111001101100000001
31112111202020112121120121
412110120122321230001
524103221024331423
6531245214540241
743240626010423
oct6243032715401
91474666477517
10434201402113
1115816440aa86
1270199207681
1331c3928039b
14170305ca813
15b4642cc45d
hex65186b9b01

434201402113 has 8 divisors (see below), whose sum is σ = 453325074048. Its totient is φ = 415098176064.

The previous prime is 434201402111. The next prime is 434201402137. The reversal of 434201402113 is 311204102434.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 434201402113 - 21 = 434201402111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (434201402111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5068056 + ... + 5153017.

It is an arithmetic number, because the mean of its divisors is an integer number (56665634256).

Almost surely, 2434201402113 is an apocalyptic number.

It is an amenable number.

434201402113 is a deficient number, since it is larger than the sum of its proper divisors (19123671935).

434201402113 is a wasteful number, since it uses less digits than its factorization.

434201402113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10222943.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 434201402113 its reverse (311204102434), we get a palindrome (745405504547).

The spelling of 434201402113 in words is "four hundred thirty-four billion, two hundred one million, four hundred two thousand, one hundred thirteen".

Divisors: 1 23 1847 42481 10221073 235084679 18878321831 434201402113