Base | Representation |
---|---|
bin | 1100101000111100101… |
… | …11110010000010001111 |
3 | 1112112000012102021212202 |
4 | 12110132113302002033 |
5 | 24103422104411011 |
6 | 531303142552115 |
7 | 43243250460266 |
oct | 6243627620217 |
9 | 1475005367782 |
10 | 434301247631 |
11 | 158205806439 |
12 | 7020673863b |
13 | 31c53b6b784 |
14 | 1703d97b5dd |
15 | b46ce5123b |
hex | 651e5f208f |
434301247631 has 2 divisors, whose sum is σ = 434301247632. Its totient is φ = 434301247630.
The previous prime is 434301247577. The next prime is 434301247669. The reversal of 434301247631 is 136742103434.
It is an a-pointer prime, because the next prime (434301247669) can be obtained adding 434301247631 to its sum of digits (38).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 434301247631 - 222 = 434297053327 is a prime.
It is a super-2 number, since 2×4343012476312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (434301241631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 217150623815 + 217150623816.
It is an arithmetic number, because the mean of its divisors is an integer number (217150623816).
Almost surely, 2434301247631 is an apocalyptic number.
434301247631 is a deficient number, since it is larger than the sum of its proper divisors (1).
434301247631 is an equidigital number, since it uses as much as digits as its factorization.
434301247631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 145152, while the sum is 38.
The spelling of 434301247631 in words is "four hundred thirty-four billion, three hundred one million, two hundred forty-seven thousand, six hundred thirty-one".
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