4344030120132 has 72 divisors (see below), whose sum is σ = 10988968536000. Its totient is φ = 1446925791168.

The previous prime is 4344030120127. The next prime is 4344030120137. The reversal of 4344030120132 is 2310210304434.

4344030120132 is a `hidden beast` number, since 4 + 3 + 4 + 403 + 0 + 120 + 132 = 666.

It is an interprime number because it is at equal distance from previous prime (4344030120127) and next prime (4344030120137).

It is a super-3 number, since 3×4344030120132³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 4344030120096 and 4344030120105.

It is not an unprimeable number, because it can be changed into a prime (4344030120137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 331624119 + ... + 331637217.

It is an arithmetic number, because the mean of its divisors is an integer number (152624563000).

Almost surely, 2^{4344030120132} is an apocalyptic number.

It is an amenable number.

4344030120132 is an abundant number, since it is smaller than the sum of its proper divisors (6644938415868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4344030120132 is a wasteful number, since it uses less digits than its factorization.

4344030120132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19305 (or 19300 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 4344030120132 its reverse (2310210304434), we get a palindrome (6654240424566).

The spelling of 4344030120132 in words is "four trillion, three hundred forty-four billion, thirty million, one hundred twenty thousand, one hundred thirty-two".