Base | Representation |
---|---|
bin | 111111010100010010100… |
… | …111111000010100101111 |
3 | 120101221222122012222012002 |
4 | 333110102213320110233 |
5 | 1032242040231040210 |
6 | 13130512504202515 |
7 | 626233445305244 |
oct | 77242247702457 |
9 | 16357878188162 |
10 | 4351114315055 |
11 | 142832a663352 |
12 | 5a333746943b |
13 | 2574014ba681 |
14 | 110848b995cb |
15 | 782b0c714a5 |
hex | 3f5129f852f |
4351114315055 has 4 divisors (see below), whose sum is σ = 5221337178072. Its totient is φ = 3480891452040.
The previous prime is 4351114315007. The next prime is 4351114315057. The reversal of 4351114315055 is 5505134111534.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 4351114315055 - 228 = 4350845879599 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4351114315057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435111431501 + ... + 435111431510.
It is an arithmetic number, because the mean of its divisors is an integer number (1305334294518).
Almost surely, 24351114315055 is an apocalyptic number.
4351114315055 is a deficient number, since it is larger than the sum of its proper divisors (870222863017).
4351114315055 is an equidigital number, since it uses as much as digits as its factorization.
4351114315055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 870222863016.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 4351114315055 its reverse (5505134111534), we get a palindrome (9856248426589).
The spelling of 4351114315055 in words is "four trillion, three hundred fifty-one billion, one hundred fourteen million, three hundred fifteen thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •