Base | Representation |
---|---|
bin | 110001011101111000110101… |
… | …1000001100110011110010101 |
3 | 2010001121201100000211112110120 |
4 | 1202323301223001212132111 |
5 | 424012421232123430023 |
6 | 4141225404352142153 |
7 | 160436055406245123 |
oct | 14273615301463625 |
9 | 2101551300745416 |
10 | 435116342405013 |
11 | 116706893912055 |
12 | 40974566837959 |
13 | 158a33ab241119 |
14 | 7963a59a20913 |
15 | 35485944428e3 |
hex | 18bbc6b066795 |
435116342405013 has 64 divisors (see below), whose sum is σ = 616441581010944. Its totient is φ = 272603397528000.
The previous prime is 435116342404993. The next prime is 435116342405057. The reversal of 435116342405013 is 310504243611534.
It is not a de Polignac number, because 435116342405013 - 29 = 435116342404501 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (435116342405083) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 4071362968 + ... + 4071469838.
It is an arithmetic number, because the mean of its divisors is an integer number (9631899703296).
Almost surely, 2435116342405013 is an apocalyptic number.
It is an amenable number.
435116342405013 is a deficient number, since it is larger than the sum of its proper divisors (181325238605931).
435116342405013 is a wasteful number, since it uses less digits than its factorization.
435116342405013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116246.
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 435116342405013 in words is "four hundred thirty-five trillion, one hundred sixteen billion, three hundred forty-two million, four hundred five thousand, thirteen".
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