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43539268147 = 229611896227
BaseRepresentation
bin101000100011001001…
…001000001000110011
311011101022210222122221
4220203021020020303
51203132023040042
632000205341511
73100641446554
oct504311101063
9134338728587
1043539268147
1117512866641
128531267897
13414b3ba57b
14217066c32b
1511ec59dd67
hexa23248233

43539268147 has 4 divisors (see below), whose sum is σ = 43541187336. Its totient is φ = 43537348960.

The previous prime is 43539268127. The next prime is 43539268153. The reversal of 43539268147 is 74186293534.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 74186293534 = 237093146767.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-43539268147 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43539268094 and 43539268103.

It is not an unprimeable number, because it can be changed into a prime (43539268127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 925153 + ... + 971074.

It is an arithmetic number, because the mean of its divisors is an integer number (10885296834).

Almost surely, 243539268147 is an apocalyptic number.

43539268147 is a deficient number, since it is larger than the sum of its proper divisors (1919189).

43539268147 is a wasteful number, since it uses less digits than its factorization.

43539268147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919188.

The product of its digits is 4354560, while the sum is 52.

The spelling of 43539268147 in words is "forty-three billion, five hundred thirty-nine million, two hundred sixty-eight thousand, one hundred forty-seven".

Divisors: 1 22961 1896227 43539268147