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4383222013117 is a prime number
BaseRepresentation
bin111111110010001100011…
…001000001110010111101
3120112000212021112000202101
4333302030121001302331
51033303314313404432
613153342511425101
7631451220242353
oct77621431016275
916460767460671
104383222013117
11143aa06613102
125a95b8225191
1325a44a43748c
141122130d57d3
157903e9334e7
hex3fc8c641cbd

4383222013117 has 2 divisors, whose sum is σ = 4383222013118. Its totient is φ = 4383222013116.

The previous prime is 4383222013109. The next prime is 4383222013133. The reversal of 4383222013117 is 7113102223834.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2693583393796 + 1689638619321 = 1641214^2 + 1299861^2 .

It is a cyclic number.

It is not a de Polignac number, because 4383222013117 - 23 = 4383222013109 is a prime.

It is a super-2 number, since 2×43832220131172 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4383222113117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2191611006558 + 2191611006559.

It is an arithmetic number, because the mean of its divisors is an integer number (2191611006559).

Almost surely, 24383222013117 is an apocalyptic number.

It is an amenable number.

4383222013117 is a deficient number, since it is larger than the sum of its proper divisors (1).

4383222013117 is an equidigital number, since it uses as much as digits as its factorization.

4383222013117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48384, while the sum is 37.

The spelling of 4383222013117 in words is "four trillion, three hundred eighty-three billion, two hundred twenty-two million, thirteen thousand, one hundred seventeen".