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44014554113 is a prime number
BaseRepresentation
bin101000111111011110…
…001100110000000001
311012121110011000102212
4220333132030300001
51210120211212423
632115304351505
73115502352125
oct507736146001
9135543130385
1044014554113
1117737082a62
128644475595
1341c59cb67a
1421b782d585
151229184578
hexa3f78cc01

44014554113 has 2 divisors, whose sum is σ = 44014554114. Its totient is φ = 44014554112.

The previous prime is 44014554107. The next prime is 44014554119. The reversal of 44014554113 is 31145541044.

It is a balanced prime because it is at equal distance from previous prime (44014554107) and next prime (44014554119).

It can be written as a sum of positive squares in only one way, i.e., 36912784129 + 7101769984 = 192127^2 + 84272^2 .

It is a cyclic number.

It is not a de Polignac number, because 44014554113 - 212 = 44014550017 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 44014554113.

It is not a weakly prime, because it can be changed into another prime (44014554119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22007277056 + 22007277057.

It is an arithmetic number, because the mean of its divisors is an integer number (22007277057).

Almost surely, 244014554113 is an apocalyptic number.

It is an amenable number.

44014554113 is a deficient number, since it is larger than the sum of its proper divisors (1).

44014554113 is an equidigital number, since it uses as much as digits as its factorization.

44014554113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 32.

The spelling of 44014554113 in words is "forty-four billion, fourteen million, five hundred fifty-four thousand, one hundred thirteen".