Base | Representation |
---|---|
bin | 100000000010110111110… |
… | …0000000000011111110101 |
3 | 120121001001010010221202221 |
4 | 1000011233200000133311 |
5 | 1034124311301440041 |
6 | 13211133411002341 |
7 | 633123324336541 |
oct | 100055740003765 |
9 | 16531033127687 |
10 | 4404212140021 |
11 | 14488a7a32121 |
12 | 5b16958993b1 |
13 | 25c413ca3405 |
14 | 113244ab8a21 |
15 | 7986c5802d1 |
hex | 4016f8007f5 |
4404212140021 has 2 divisors, whose sum is σ = 4404212140022. Its totient is φ = 4404212140020.
The previous prime is 4404212139937. The next prime is 4404212140033. The reversal of 4404212140021 is 1200412124044.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3278036986225 + 1126175153796 = 1810535^2 + 1061214^2 .
It is a cyclic number.
It is not a de Polignac number, because 4404212140021 - 213 = 4404212131829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4404212140061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2202106070010 + 2202106070011.
It is an arithmetic number, because the mean of its divisors is an integer number (2202106070011).
Almost surely, 24404212140021 is an apocalyptic number.
It is an amenable number.
4404212140021 is a deficient number, since it is larger than the sum of its proper divisors (1).
4404212140021 is an equidigital number, since it uses as much as digits as its factorization.
4404212140021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2048, while the sum is 25.
Adding to 4404212140021 its reverse (1200412124044), we get a palindrome (5604624264065).
The spelling of 4404212140021 in words is "four trillion, four hundred four billion, two hundred twelve million, one hundred forty thousand, twenty-one".
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