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440640000013 is a prime number
BaseRepresentation
bin1100110100110000011…
…00001101000000001101
31120010100221220021110111
412122120030031000031
524204412320000023
6534232140240021
743556320126033
oct6323014150015
91503327807414
10440640000013
1115a968879974
1271495540011
1332724183025
141748176a553
15b6de6a000d
hex669830d00d

440640000013 has 2 divisors, whose sum is σ = 440640000014. Its totient is φ = 440640000012.

The previous prime is 440639999927. The next prime is 440640000049. The reversal of 440640000013 is 310000046044.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 438049393609 + 2590606404 = 661853^2 + 50898^2 .

It is a cyclic number.

It is not a de Polignac number, because 440640000013 - 213 = 440639991821 is a prime.

It is a super-2 number, since 2×4406400000132 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (440640000313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220320000006 + 220320000007.

It is an arithmetic number, because the mean of its divisors is an integer number (220320000007).

Almost surely, 2440640000013 is an apocalyptic number.

It is an amenable number.

440640000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

440640000013 is an equidigital number, since it uses as much as digits as its factorization.

440640000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 440640000013 its reverse (310000046044), we get a palindrome (750640046057).

The spelling of 440640000013 in words is "four hundred forty billion, six hundred forty million, thirteen", and thus it is an aban number.