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44110000133 is a prime number
BaseRepresentation
bin101001000101001010…
…010011000000000101
311012212002202011202122
4221011022103000011
51210314130001013
632132554215325
73121041546323
oct510512230005
9135762664678
1044110000133
1117785a43a71
128670424545
13420c7093c4
1421c6396d13
151232739a08
hexa45293005

44110000133 has 2 divisors, whose sum is σ = 44110000134. Its totient is φ = 44110000132.

The previous prime is 44110000061. The next prime is 44110000141. The reversal of 44110000133 is 33100001144.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44033664964 + 76335169 = 209842^2 + 8737^2 .

It is a cyclic number.

It is not a de Polignac number, because 44110000133 - 218 = 44109737989 is a prime.

It is a super-2 number, since 2×441100001332 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44110000633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22055000066 + 22055000067.

It is an arithmetic number, because the mean of its divisors is an integer number (22055000067).

Almost surely, 244110000133 is an apocalyptic number.

It is an amenable number.

44110000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

44110000133 is an equidigital number, since it uses as much as digits as its factorization.

44110000133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 44110000133 its reverse (33100001144), we get a palindrome (77210001277).

The spelling of 44110000133 in words is "forty-four billion, one hundred ten million, one hundred thirty-three", and thus it is an aban number.