Base | Representation |
---|---|
bin | 10100000011111000101110… |
… | …10111111011000010011001 |
3 | 12210012020221121001221221112 |
4 | 22001330113113323002121 |
5 | 21240230433304304223 |
6 | 233453405320350105 |
7 | 12202063034455460 |
oct | 1201742727730231 |
9 | 183166847057845 |
10 | 44114001244313 |
11 | 1306870871a930 |
12 | 4b45709915335 |
13 | 1b7cc17828c80 |
14 | ac71b41979d7 |
15 | 51778e1dd778 |
hex | 281f175fb099 |
44114001244313 has 64 divisors (see below), whose sum is σ = 59361360758784. Its totient is φ = 31660009920000.
The previous prime is 44114001244241. The next prime is 44114001244333. The reversal of 44114001244313 is 31344210041144.
It is not a de Polignac number, because 44114001244313 - 226 = 44113934135449 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 44114001244313.
It is not an unprimeable number, because it can be changed into a prime (44114001244333) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2016076133 + ... + 2016098013.
It is an arithmetic number, because the mean of its divisors is an integer number (927521261856).
Almost surely, 244114001244313 is an apocalyptic number.
It is an amenable number.
44114001244313 is a deficient number, since it is larger than the sum of its proper divisors (15247359514471).
44114001244313 is a wasteful number, since it uses less digits than its factorization.
44114001244313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26286.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 44114001244313 its reverse (31344210041144), we get a palindrome (75458211285457).
The spelling of 44114001244313 in words is "forty-four trillion, one hundred fourteen billion, one million, two hundred forty-four thousand, three hundred thirteen".
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