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4414142414113 is a prime number
BaseRepresentation
bin100000000111011111101…
…1000111111110100100001
3120121222200011201010221021
41000032333120333310201
51034310130424222423
613215455023125441
7633624364306135
oct100167730776441
916558604633837
104414142414113
111452033353013
125b35a7443881
132603373b9a43
1411390788b3c5
1579c4e26895d
hex403bf63fd21

4414142414113 has 2 divisors, whose sum is σ = 4414142414114. Its totient is φ = 4414142414112.

The previous prime is 4414142414111. The next prime is 4414142414197. The reversal of 4414142414113 is 3114142414144.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2302721270784 + 2111421143329 = 1517472^2 + 1453073^2 .

It is a cyclic number.

It is not a de Polignac number, because 4414142414113 - 21 = 4414142414111 is a prime.

Together with 4414142414111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (4414142414111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2207071207056 + 2207071207057.

It is an arithmetic number, because the mean of its divisors is an integer number (2207071207057).

Almost surely, 24414142414113 is an apocalyptic number.

It is an amenable number.

4414142414113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4414142414113 is an equidigital number, since it uses as much as digits as its factorization.

4414142414113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 24576, while the sum is 34.

Adding to 4414142414113 its reverse (3114142414144), we get a palindrome (7528284828257).

The spelling of 4414142414113 in words is "four trillion, four hundred fourteen billion, one hundred forty-two million, four hundred fourteen thousand, one hundred thirteen".