441542121331 has 2 divisors, whose sum is σ = 441542121332. Its totient is φ = 441542121330.

The previous prime is 441542121329. The next prime is 441542121343. The reversal of 441542121331 is 133121245144.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 441542121331 - 2¹ = 441542121329 is a prime.

It is a super-2 number, since 2×441542121331² (a number of 24 digits) contains 22 as substring.

Together with 441542121329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 441542121293 and 441542121302.

It is not a weakly prime, because it can be changed into another prime (441522121331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 220771060665 + 220771060666.

It is an arithmetic number, because the mean of its divisors is an integer number (220771060666).

Almost surely, 2^441542121331 is an apocalyptic number.

441542121331 is a deficient number, since it is larger than the sum of its proper divisors (1).

441542121331 is an equidigital number, since it uses as much as digits as its factorization.

441542121331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11520, while the sum is 31.

Adding to 441542121331 its reverse (133121245144), we get a palindrome (574663366475).

The spelling of 441542121331 in words is "four hundred forty-one billion, five hundred forty-two million, one hundred twenty-one thousand, three hundred thirty-one".