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4421214121241 is a prime number
BaseRepresentation
bin100000001010110010011…
…1001011010110100011001
3120122122221000101002102002
41000111210321122310121
51034414121303334431
613223024442250345
7634264543652111
oct100254471326431
916578830332362
104421214121241
111455032124275
125b4a3b7b69b5
13260bc350b528
14113db8b52041
157a014ee93cb
hex40564e5ad19

4421214121241 has 2 divisors, whose sum is σ = 4421214121242. Its totient is φ = 4421214121240.

The previous prime is 4421214121211. The next prime is 4421214121243. The reversal of 4421214121241 is 1421214121244.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4232318707600 + 188895413641 = 2057260^2 + 434621^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4421214121241 is a prime.

Together with 4421214121243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4421214121243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2210607060620 + 2210607060621.

It is an arithmetic number, because the mean of its divisors is an integer number (2210607060621).

Almost surely, 24421214121241 is an apocalyptic number.

It is an amenable number.

4421214121241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4421214121241 is an equidigital number, since it uses as much as digits as its factorization.

4421214121241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4096, while the sum is 29.

Adding to 4421214121241 its reverse (1421214121244), we get a palindrome (5842428242485).

The spelling of 4421214121241 in words is "four trillion, four hundred twenty-one billion, two hundred fourteen million, one hundred twenty-one thousand, two hundred forty-one".