Base | Representation |
---|---|
bin | 100000001010110010011… |
… | …1001011010110100011011 |
3 | 120122122221000101002102011 |
4 | 1000111210321122310123 |
5 | 1034414121303334433 |
6 | 13223024442250351 |
7 | 634264543652113 |
oct | 100254471326433 |
9 | 16578830332364 |
10 | 4421214121243 |
11 | 1455032124277 |
12 | 5b4a3b7b69b7 |
13 | 260bc350b52a |
14 | 113db8b52043 |
15 | 7a014ee93cd |
hex | 40564e5ad1b |
4421214121243 has 2 divisors, whose sum is σ = 4421214121244. Its totient is φ = 4421214121242.
The previous prime is 4421214121241. The next prime is 4421214121297. The reversal of 4421214121243 is 3421214121244.
4421214121243 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4421214121243 - 21 = 4421214121241 is a prime.
Together with 4421214121241, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4421214121241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2210607060621 + 2210607060622.
It is an arithmetic number, because the mean of its divisors is an integer number (2210607060622).
Almost surely, 24421214121243 is an apocalyptic number.
4421214121243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4421214121243 is an equidigital number, since it uses as much as digits as its factorization.
4421214121243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12288, while the sum is 31.
Adding to 4421214121243 its reverse (3421214121244), we get a palindrome (7842428242487).
Subtracting from 4421214121243 its reverse (3421214121244), we obtain a palindrome (999999999999).
The spelling of 4421214121243 in words is "four trillion, four hundred twenty-one billion, two hundred fourteen million, one hundred twenty-one thousand, two hundred forty-three".
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