Base | Representation |
---|---|
bin | 100000001010110110000… |
… | …0011111110111011100111 |
3 | 120122200020101120101100111 |
4 | 1000111230003332323213 |
5 | 1034414343042043421 |
6 | 13223044414553451 |
7 | 634300533506155 |
oct | 100255403767347 |
9 | 16580211511314 |
10 | 4421334331111 |
11 | 1455093a69775 |
12 | 5b4a73b08887 |
13 | 260c123a9b29 |
14 | 113dcaac43d5 |
15 | 7a020841ee1 |
hex | 4056c0feee7 |
4421334331111 has 2 divisors, whose sum is σ = 4421334331112. Its totient is φ = 4421334331110.
The previous prime is 4421334331103. The next prime is 4421334331147. The reversal of 4421334331111 is 1111334331244.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4421334331111 - 23 = 4421334331103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4421334332111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2210667165555 + 2210667165556.
It is an arithmetic number, because the mean of its divisors is an integer number (2210667165556).
Almost surely, 24421334331111 is an apocalyptic number.
4421334331111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4421334331111 is an equidigital number, since it uses as much as digits as its factorization.
4421334331111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 31.
Adding to 4421334331111 its reverse (1111334331244), we get a palindrome (5532668662355).
The spelling of 4421334331111 in words is "four trillion, four hundred twenty-one billion, three hundred thirty-four million, three hundred thirty-one thousand, one hundred eleven".
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