Base | Representation |
---|---|
bin | 100000001010110110000… |
… | …0011111110111101000111 |
3 | 120122200020101120101111001 |
4 | 1000111230003332331013 |
5 | 1034414343042044312 |
6 | 13223044414554131 |
7 | 634300533506353 |
oct | 100255403767507 |
9 | 16580211511431 |
10 | 4421334331207 |
11 | 1455093a69852 |
12 | 5b4a73b08947 |
13 | 260c123a9ba1 |
14 | 113dcaac4463 |
15 | 7a020842057 |
hex | 4056c0fef47 |
4421334331207 has 4 divisors (see below), whose sum is σ = 4681412821296. Its totient is φ = 4161255841120.
The previous prime is 4421334331147. The next prime is 4421334331213. The reversal of 4421334331207 is 7021334331244.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-4421334331207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4421334331217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130039245019 + ... + 130039245052.
It is an arithmetic number, because the mean of its divisors is an integer number (1170353205324).
Almost surely, 24421334331207 is an apocalyptic number.
4421334331207 is a deficient number, since it is larger than the sum of its proper divisors (260078490089).
4421334331207 is a wasteful number, since it uses less digits than its factorization.
4421334331207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260078490088.
The product of its (nonzero) digits is 145152, while the sum is 37.
Adding to 4421334331207 its sum of digits (37), we get a palindrome (4421334331244).
The spelling of 4421334331207 in words is "four trillion, four hundred twenty-one billion, three hundred thirty-four million, three hundred thirty-one thousand, two hundred seven".
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