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44310023101 = 192332106479
BaseRepresentation
bin101001010001000101…
…010100101110111101
311020101001010101200201
4221101011110232331
51211221331214401
632204501323501
73126020660551
oct512105245675
9136331111621
1044310023101
1117878942203
128707406591
134241ca0ca6
142204b83861
15124509ab01
hexa51154bbd

44310023101 has 4 divisors (see below), whose sum is σ = 46642129600. Its totient is φ = 41977916604.

The previous prime is 44310023083. The next prime is 44310023123. The reversal of 44310023101 is 10132001344.

44310023101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-44310023101 is a prime.

It is a super-2 number, since 2×443100231012 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 2332106479 = 44310023101 / (4 + 4 + 3 + 1 + 0 + 0 + 2 + 3 + 1 + 0 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (44310023171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1166053221 + ... + 1166053258.

It is an arithmetic number, because the mean of its divisors is an integer number (11660532400).

Almost surely, 244310023101 is an apocalyptic number.

It is an amenable number.

44310023101 is a deficient number, since it is larger than the sum of its proper divisors (2332106499).

44310023101 is a wasteful number, since it uses less digits than its factorization.

44310023101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2332106498.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 44310023101 its reverse (10132001344), we get a palindrome (54442024445).

The spelling of 44310023101 in words is "forty-four billion, three hundred ten million, twenty-three thousand, one hundred one".

Divisors: 1 19 2332106479 44310023101