Base | Representation |
---|---|
bin | 100000001111011100011… |
… | …0000110111101111010111 |
3 | 120200121201201110021201222 |
4 | 1000132320300313233113 |
5 | 1040100110020214033 |
6 | 13231400440240555 |
7 | 635100353615111 |
oct | 100367060675727 |
9 | 16617651407658 |
10 | 4431211101143 |
11 | 14592a2166232 |
12 | 5b696b77015b |
13 | 261b276ac158 |
14 | 11468672a3b1 |
15 | 7a3ec9ac598 |
hex | 407b8c37bd7 |
4431211101143 has 2 divisors, whose sum is σ = 4431211101144. Its totient is φ = 4431211101142.
The previous prime is 4431211101101. The next prime is 4431211101169. The reversal of 4431211101143 is 3411011121344.
It is an a-pointer prime, because the next prime (4431211101169) can be obtained adding 4431211101143 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4431211101143 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4431211101193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2215605550571 + 2215605550572.
It is an arithmetic number, because the mean of its divisors is an integer number (2215605550572).
Almost surely, 24431211101143 is an apocalyptic number.
4431211101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
4431211101143 is an equidigital number, since it uses as much as digits as its factorization.
4431211101143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 4431211101143 its reverse (3411011121344), we get a palindrome (7842222222487).
It can be divided in two parts, 4431211 and 101143, that added together give a palindrome (4532354).
The spelling of 4431211101143 in words is "four trillion, four hundred thirty-one billion, two hundred eleven million, one hundred one thousand, one hundred forty-three".
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