Base | Representation |
---|---|
bin | 100000001111011100011… |
… | …1001000010101011100000 |
3 | 120200121201212111002221212 |
4 | 1000132320321002223200 |
5 | 1040100111042234404 |
6 | 13231400554205252 |
7 | 635100411045644 |
oct | 100367071025340 |
9 | 16617655432855 |
10 | 4431213243104 |
11 | 14592a339954a |
12 | 5b6970423828 |
13 | 261b27c7c09b |
14 | 114686b26c24 |
15 | 7a3ecc8206e |
hex | 407b8e42ae0 |
4431213243104 has 48 divisors (see below), whose sum is σ = 8912368797696. Its totient is φ = 2167784150400.
The previous prime is 4431213243059. The next prime is 4431213243109. The reversal of 4431213243104 is 4013423121344.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4431213243109) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4337609 + ... + 5260919.
It is an arithmetic number, because the mean of its divisors is an integer number (185674349952).
Almost surely, 24431213243104 is an apocalyptic number.
It is an amenable number.
4431213243104 is an abundant number, since it is smaller than the sum of its proper divisors (4481155554592).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4431213243104 is a wasteful number, since it uses less digits than its factorization.
4431213243104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 926559 (or 926551 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4431213243104 its reverse (4013423121344), we get a palindrome (8444636364448).
The spelling of 4431213243104 in words is "four trillion, four hundred thirty-one billion, two hundred thirteen million, two hundred forty-three thousand, one hundred four".
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