Base | Representation |
---|---|
bin | 101001010001001101… |
… | …011010000101001001 |
3 | 11020101012010001111010 |
4 | 221101031122011021 |
5 | 1211222402022103 |
6 | 32205014554133 |
7 | 3126044664546 |
oct | 512115320511 |
9 | 136335101433 |
10 | 44312142153 |
11 | 1787a05a294 |
12 | 8708068949 |
13 | 4242563676 |
14 | 2205175bcd |
15 | 1245368903 |
hex | a5135a149 |
44312142153 has 4 divisors (see below), whose sum is σ = 59082856208. Its totient is φ = 29541428100.
The previous prime is 44312142103. The next prime is 44312142169. The reversal of 44312142153 is 35124121344.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 44312142153 - 213 = 44312133961 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 44312142153.
It is not an unprimeable number, because it can be changed into a prime (44312142103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7385357023 + ... + 7385357028.
It is an arithmetic number, because the mean of its divisors is an integer number (14770714052).
Almost surely, 244312142153 is an apocalyptic number.
It is an amenable number.
44312142153 is a deficient number, since it is larger than the sum of its proper divisors (14770714055).
44312142153 is a wasteful number, since it uses less digits than its factorization.
44312142153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14770714054.
The product of its digits is 11520, while the sum is 30.
Adding to 44312142153 its reverse (35124121344), we get a palindrome (79436263497).
The spelling of 44312142153 in words is "forty-four billion, three hundred twelve million, one hundred forty-two thousand, one hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •