Base | Representation |
---|---|
bin | 10100001001101101010010… |
… | …00000001110000101010101 |
3 | 12210220101012202110220020112 |
4 | 22010312221000032011111 |
5 | 21302020044312000041 |
6 | 234125324310412405 |
7 | 12222403360363622 |
oct | 1204665100160525 |
9 | 183811182426215 |
10 | 44314013000021 |
11 | 13135516090296 |
12 | 4b78429361105 |
13 | 1b95a41402b8b |
14 | ad2b49a59349 |
15 | 51ca986d5deb |
hex | 284da900e155 |
44314013000021 has 4 divisors (see below), whose sum is σ = 44314160557344. Its totient is φ = 44313865442700.
The previous prime is 44314012999987. The next prime is 44314013000051. The reversal of 44314013000021 is 12000031041344.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 44314013000021 - 226 = 44313945891157 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (44314013000051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73327265 + ... + 73929126.
It is an arithmetic number, because the mean of its divisors is an integer number (11078540139336).
Almost surely, 244314013000021 is an apocalyptic number.
It is an amenable number.
44314013000021 is a deficient number, since it is larger than the sum of its proper divisors (147557323).
44314013000021 is a wasteful number, since it uses less digits than its factorization.
44314013000021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147557322.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 44314013000021 its reverse (12000031041344), we get a palindrome (56314044041365).
The spelling of 44314013000021 in words is "forty-four trillion, three hundred fourteen billion, thirteen million, twenty-one", and thus it is an aban number.
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