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443146360770133 is a prime number
BaseRepresentation
bin110010011000010100000110…
…1011010101100111001010101
32011010001101012211001212220121
41210300220031122230321111
5431041002221324121013
64210254343330031541
7162225160634203006
oct14460501532547125
92133041184055817
10443146360770133
111192223529422a9
12418508977185b1
13160366a3c5a5b7
147b60580d291ad
1536373c190d58d
hex1930a0d6ace55

443146360770133 has 2 divisors, whose sum is σ = 443146360770134. Its totient is φ = 443146360770132.

The previous prime is 443146360770107. The next prime is 443146360770137. The reversal of 443146360770133 is 331077063641344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 352180508859729 + 90965851910404 = 18766473^2 + 9537602^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-443146360770133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443146360770137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221573180385066 + 221573180385067.

It is an arithmetic number, because the mean of its divisors is an integer number (221573180385067).

Almost surely, 2443146360770133 is an apocalyptic number.

It is an amenable number.

443146360770133 is a deficient number, since it is larger than the sum of its proper divisors (1).

443146360770133 is an equidigital number, since it uses as much as digits as its factorization.

443146360770133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9144576, while the sum is 52.

The spelling of 443146360770133 in words is "four hundred forty-three trillion, one hundred forty-six billion, three hundred sixty million, seven hundred seventy thousand, one hundred thirty-three".