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44325000409 = 431030813963
BaseRepresentation
bin101001010001111110…
…011101010011011001
311020102002022022200211
4221101332131103121
51211234200003114
632210154331121
73126262200304
oct512176352331
9136362268624
1044325000409
1117886341948
128710429aa1
1342451161c1
142206b61b3b
1512465586c4
hexa51f9d4d9

44325000409 has 4 divisors (see below), whose sum is σ = 45355814416. Its totient is φ = 43294186404.

The previous prime is 44325000407. The next prime is 44325000427. The reversal of 44325000409 is 90400052344.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 44325000409 - 21 = 44325000407 is a prime.

It is a super-2 number, since 2×443250004092 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (44325000403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515406939 + ... + 515407024.

It is an arithmetic number, because the mean of its divisors is an integer number (11338953604).

Almost surely, 244325000409 is an apocalyptic number.

It is an amenable number.

44325000409 is a deficient number, since it is larger than the sum of its proper divisors (1030814007).

44325000409 is a wasteful number, since it uses less digits than its factorization.

44325000409 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1030814006.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 44325000409 in words is "forty-four billion, three hundred twenty-five million, four hundred nine", and thus it is an aban number.

Divisors: 1 43 1030813963 44325000409