Base | Representation |
---|---|
bin | 101001010010000011… |
… | …110110000100000001 |
3 | 11020102011222001210011 |
4 | 221102003312010001 |
5 | 1211240030200140 |
6 | 32210244504521 |
7 | 3126310201312 |
oct | 512203660401 |
9 | 136364861704 |
10 | 44326412545 |
11 | 178871168a8 |
12 | 87109ab141 |
13 | 42454bbb9c |
14 | 220700c609 |
15 | 1246736cea |
hex | a520f6101 |
44326412545 has 4 divisors (see below), whose sum is σ = 53191695060. Its totient is φ = 35461130032.
The previous prime is 44326412509. The next prime is 44326412573. The reversal of 44326412545 is 54521462344.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 29278974321 + 15047438224 = 171111^2 + 122668^2 .
It is a cyclic number.
It is not a de Polignac number, because 44326412545 - 217 = 44326281473 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 44326412498 and 44326412507.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4432641250 + ... + 4432641259.
It is an arithmetic number, because the mean of its divisors is an integer number (13297923765).
Almost surely, 244326412545 is an apocalyptic number.
It is an amenable number.
44326412545 is a deficient number, since it is larger than the sum of its proper divisors (8865282515).
44326412545 is an equidigital number, since it uses as much as digits as its factorization.
44326412545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8865282514.
The product of its digits is 460800, while the sum is 40.
Adding to 44326412545 its reverse (54521462344), we get a palindrome (98847874889).
The spelling of 44326412545 in words is "forty-four billion, three hundred twenty-six million, four hundred twelve thousand, five hundred forty-five".
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