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443320032354013 is a prime number
BaseRepresentation
bin110010011001100100111110…
…1000011001101111011011101
32011010122222111021210110021001
41210303021331003031323131
5431101323411240312023
64210510224502510301
7162243546450254233
oct14463117503157335
92133588437713231
10443320032354013
11119289a73a30811
124187a485a35391
1316049b90769209
147b68b38466953
15363bb8875a6ad
hex193327d0cdedd

443320032354013 has 2 divisors, whose sum is σ = 443320032354014. Its totient is φ = 443320032354012.

The previous prime is 443320032354011. The next prime is 443320032354071. The reversal of 443320032354013 is 310453230023344.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 241084840986649 + 202235191367364 = 15526907^2 + 14220942^2 .

It is a cyclic number.

It is not a de Polignac number, because 443320032354013 - 21 = 443320032354011 is a prime.

Together with 443320032354011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (443320032354011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 221660016177006 + 221660016177007.

It is an arithmetic number, because the mean of its divisors is an integer number (221660016177007).

Almost surely, 2443320032354013 is an apocalyptic number.

It is an amenable number.

443320032354013 is a deficient number, since it is larger than the sum of its proper divisors (1).

443320032354013 is an equidigital number, since it uses as much as digits as its factorization.

443320032354013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 37.

Adding to 443320032354013 its reverse (310453230023344), we get a palindrome (753773262377357).

The spelling of 443320032354013 in words is "four hundred forty-three trillion, three hundred twenty billion, thirty-two million, three hundred fifty-four thousand, thirteen".