Search a number
-
+
44341311437 is a prime number
BaseRepresentation
bin101001010010111100…
…101011011111001101
311020110020000000012222
4221102330223133031
51211302333431222
632211540105125
73126550633313
oct512274533715
9136406000188
1044341311437
1117894572635
1287159951a5
1342486074b7
142208daa0b3
151247bcb542
hexa52f2b7cd

44341311437 has 2 divisors, whose sum is σ = 44341311438. Its totient is φ = 44341311436.

The previous prime is 44341311367. The next prime is 44341311439. The reversal of 44341311437 is 73411314344.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34875189001 + 9466122436 = 186749^2 + 97294^2 .

It is a cyclic number.

It is not a de Polignac number, because 44341311437 - 28 = 44341311181 is a prime.

Together with 44341311439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 44341311397 and 44341311406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44341311439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22170655718 + 22170655719.

It is an arithmetic number, because the mean of its divisors is an integer number (22170655719).

Almost surely, 244341311437 is an apocalyptic number.

It is an amenable number.

44341311437 is a deficient number, since it is larger than the sum of its proper divisors (1).

44341311437 is an equidigital number, since it uses as much as digits as its factorization.

44341311437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 35.

The spelling of 44341311437 in words is "forty-four billion, three hundred forty-one million, three hundred eleven thousand, four hundred thirty-seven".