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44398889893 is a prime number
BaseRepresentation
bin101001010110011000…
…010100101110100101
311020121020100022000101
4221112120110232211
51211412103434033
632221354144101
73131150223451
oct512630245645
9136536308011
1044398889893
111791401a136
128731122031
1342575171a7
1422128b7661
15124cca197d
hexa56614ba5

44398889893 has 2 divisors, whose sum is σ = 44398889894. Its totient is φ = 44398889892.

The previous prime is 44398889839. The next prime is 44398889917. The reversal of 44398889893 is 39898889344.

Together with previous prime (44398889839) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26995475809 + 17403414084 = 164303^2 + 131922^2 .

It is a cyclic number.

It is not a de Polignac number, because 44398889893 - 213 = 44398881701 is a prime.

It is a super-2 number, since 2×443988898932 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (44398809893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 22199444946 + 22199444947.

It is an arithmetic number, because the mean of its divisors is an integer number (22199444947).

Almost surely, 244398889893 is an apocalyptic number.

It is an amenable number.

44398889893 is a deficient number, since it is larger than the sum of its proper divisors (1).

44398889893 is an equidigital number, since it uses as much as digits as its factorization.

44398889893 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 429981696, while the sum is 73.

The spelling of 44398889893 in words is "forty-four billion, three hundred ninety-eight million, eight hundred eighty-nine thousand, eight hundred ninety-three".