Base | Representation |
---|---|
bin | 100000010011101011100… |
… | …1110001011001011011101 |
3 | 120201111012222110120121202 |
4 | 1000213113032023023131 |
5 | 1040222224340042023 |
6 | 13235503505005245 |
7 | 635542033355102 |
oct | 100472716131335 |
9 | 16644188416552 |
10 | 4440312034013 |
11 | 1462142425859 |
12 | 5b868b623825 |
13 | 26294803b72b |
14 | 114cab2d6aa9 |
15 | 7a781975128 |
hex | 409d738b2dd |
4440312034013 has 2 divisors, whose sum is σ = 4440312034014. Its totient is φ = 4440312034012.
The previous prime is 4440312034007. The next prime is 4440312034021. The reversal of 4440312034013 is 3104302130444.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2791766456164 + 1648545577849 = 1670858^2 + 1283957^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4440312034013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4440312034513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2220156017006 + 2220156017007.
It is an arithmetic number, because the mean of its divisors is an integer number (2220156017007).
Almost surely, 24440312034013 is an apocalyptic number.
It is an amenable number.
4440312034013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4440312034013 is an equidigital number, since it uses as much as digits as its factorization.
4440312034013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 4440312034013 its reverse (3104302130444), we get a palindrome (7544614164457).
The spelling of 4440312034013 in words is "four trillion, four hundred forty billion, three hundred twelve million, thirty-four thousand, thirteen".
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