4442113300041 has 24 divisors (see below), whose sum is σ = 6505463652480. Its totient is φ = 2920386714336.

The previous prime is 4442113300007. The next prime is 4442113300061. The reversal of 4442113300041 is 1400033112444.

4442113300041 is a `hidden beast` number, since 444 + 211 + 3 + 3 + 0 + 0 + 0 + 4 + 1 = 666.

It is not a de Polignac number, because 4442113300041 - 2¹⁸ = 4442113037897 is a prime.

It is a super-2 number, since 2×4442113300041² (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4442113299978 and 4442113300014.

It is not an unprimeable number, because it can be changed into a prime (4442113300061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3189330 + ... + 4365323.

It is an arithmetic number, because the mean of its divisors is an integer number (271060985520).

Almost surely, 2^{4442113300041} is an apocalyptic number.

It is an amenable number.

4442113300041 is a deficient number, since it is larger than the sum of its proper divisors (2063350352439).

4442113300041 is a wasteful number, since it uses less digits than its factorization.

4442113300041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7555565 (or 7555562 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 4442113300041 its reverse (1400033112444), we get a palindrome (5842146412485).

The spelling of 4442113300041 in words is "four trillion, four hundred forty-two billion, one hundred thirteen million, three hundred thousand, forty-one".