Base | Representation |
---|---|
bin | 100000010110001000001… |
… | …0010000110010110111111 |
3 | 120201222210000120221012122 |
4 | 1000230100102012112333 |
5 | 1040314003432101310 |
6 | 13242133011553155 |
7 | 636116141223452 |
oct | 100542022062677 |
9 | 16658700527178 |
10 | 4445564331455 |
11 | 1464398195645 |
12 | 5b96b65bb7bb |
13 | 2632a4235640 |
14 | 115248ab1499 |
15 | 7a98cb16555 |
hex | 40b104865bf |
4445564331455 has 16 divisors (see below), whose sum is σ = 5765337490080. Its totient is φ = 3271277985408.
The previous prime is 4445564331427. The next prime is 4445564331487. The reversal of 4445564331455 is 5541334655444.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4445564331455 is a prime.
It is a super-2 number, since 2×44455643314552 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4445564331397 and 4445564331406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 120817820 + ... + 120854609.
It is an arithmetic number, because the mean of its divisors is an integer number (360333593130).
Almost surely, 24445564331455 is an apocalyptic number.
4445564331455 is a deficient number, since it is larger than the sum of its proper divisors (1319773158625).
4445564331455 is a wasteful number, since it uses less digits than its factorization.
4445564331455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241672730.
The product of its digits is 34560000, while the sum is 53.
Adding to 4445564331455 its reverse (5541334655444), we get a palindrome (9986898986899).
The spelling of 4445564331455 in words is "four trillion, four hundred forty-five billion, five hundred sixty-four million, three hundred thirty-one thousand, four hundred fifty-five".
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