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4500031423 is a prime number
BaseRepresentation
bin1000011000011100…
…10000011110111111
3102121121121021121111
410030032100132333
533204002001143
62022311142451
7216341431066
oct41416203677
912547537544
104500031423
1119aa172238
12a57074a27
135693b7bb4
143099171dd
151b50e799d
hex10c3907bf

4500031423 has 2 divisors, whose sum is σ = 4500031424. Its totient is φ = 4500031422.

The previous prime is 4500031411. The next prime is 4500031441. The reversal of 4500031423 is 3241300054.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4500031423 - 221 = 4497934271 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4500031394 and 4500031403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4500031463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2250015711 + 2250015712.

It is an arithmetic number, because the mean of its divisors is an integer number (2250015712).

Almost surely, 24500031423 is an apocalyptic number.

4500031423 is a deficient number, since it is larger than the sum of its proper divisors (1).

4500031423 is an equidigital number, since it uses as much as digits as its factorization.

4500031423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 22.

The square root of 4500031423 is about 67082.2735377983. The cubic root of 4500031423 is about 1650.9674672702.

Adding to 4500031423 its reverse (3241300054), we get a palindrome (7741331477).

The spelling of 4500031423 in words is "four billion, five hundred million, thirty-one thousand, four hundred twenty-three".