Base | Representation |
---|---|
bin | 1101000110010000111… |
… | …10110010000110001111 |
3 | 1121000122001212102020220 |
4 | 12203020132302012033 |
5 | 24333140232032003 |
6 | 542425013242423 |
7 | 44341261554633 |
oct | 6431036620617 |
9 | 1530561772226 |
10 | 450040111503 |
11 | 163951a01854 |
12 | 73279633413 |
13 | 335917b3588 |
14 | 17ad3d74dc3 |
15 | ba8ea63353 |
hex | 68c87b218f |
450040111503 has 4 divisors (see below), whose sum is σ = 600053482008. Its totient is φ = 300026741000.
The previous prime is 450040111501. The next prime is 450040111519. The reversal of 450040111503 is 305111040054.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 450040111503 - 21 = 450040111501 is a prime.
It is a super-2 number, since 2×4500401115032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (450040111501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75006685248 + ... + 75006685253.
It is an arithmetic number, because the mean of its divisors is an integer number (150013370502).
Almost surely, 2450040111503 is an apocalyptic number.
450040111503 is a deficient number, since it is larger than the sum of its proper divisors (150013370505).
450040111503 is a wasteful number, since it uses less digits than its factorization.
450040111503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150013370504.
The product of its (nonzero) digits is 1200, while the sum is 24.
Adding to 450040111503 its reverse (305111040054), we get a palindrome (755151151557).
The spelling of 450040111503 in words is "four hundred fifty billion, forty million, one hundred eleven thousand, five hundred three".
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