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45005313133 = 1118041226783
BaseRepresentation
bin101001111010100001…
…101001010001101101
311022011111102210022101
4221322201221101231
51214132330010013
632401500015101
73152162564314
oct517241512155
9138144383271
1045005313133
11180a5364970
128880231491
134323051601
14226d25327b
15128613c8dd
hexa7a86946d

45005313133 has 8 divisors (see below), whose sum is σ = 49099643136. Its totient is φ = 40911472800.

The previous prime is 45005313013. The next prime is 45005313139. The reversal of 45005313133 is 33131350054.

45005313133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 45005313133 - 225 = 44971758701 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (45005313139) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85060 + ... + 311842.

It is an arithmetic number, because the mean of its divisors is an integer number (6137455392).

Almost surely, 245005313133 is an apocalyptic number.

It is an amenable number.

45005313133 is a deficient number, since it is larger than the sum of its proper divisors (4094330003).

45005313133 is a wasteful number, since it uses less digits than its factorization.

45005313133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244835.

The product of its (nonzero) digits is 8100, while the sum is 28.

Adding to 45005313133 its reverse (33131350054), we get a palindrome (78136663187).

The spelling of 45005313133 in words is "forty-five billion, five million, three hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 11 18041 198451 226783 2494613 4091392103 45005313133