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450055211213 is a prime number
BaseRepresentation
bin1101000110010010110…
…00011000100011001101
31121000200010021120011102
412203021120120203031
524333203113224323
6542430313032445
744341534114256
oct6431130304315
91530603246142
10450055211213
1116395a485453
12732826b5725
133359496c40a
1417ad5d85b2d
15ba91047328
hex68c96188cd

450055211213 has 2 divisors, whose sum is σ = 450055211214. Its totient is φ = 450055211212.

The previous prime is 450055211197. The next prime is 450055211219. The reversal of 450055211213 is 312112550054.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 430962051529 + 19093159684 = 656477^2 + 138178^2 .

It is a cyclic number.

It is not a de Polignac number, because 450055211213 - 24 = 450055211197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (450055211219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 225027605606 + 225027605607.

It is an arithmetic number, because the mean of its divisors is an integer number (225027605607).

Almost surely, 2450055211213 is an apocalyptic number.

It is an amenable number.

450055211213 is a deficient number, since it is larger than the sum of its proper divisors (1).

450055211213 is an equidigital number, since it uses as much as digits as its factorization.

450055211213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 450055211213 its reverse (312112550054), we get a palindrome (762167761267).

The spelling of 450055211213 in words is "four hundred fifty billion, fifty-five million, two hundred eleven thousand, two hundred thirteen".