45010354021141 has 4 divisors (see below), whose sum is σ = 45353944509984. Its totient is φ = 44666763532300.

The previous prime is 45010354021111. The next prime is 45010354021159. The reversal of 45010354021141 is 14112045301054.

45010354021141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-45010354021141 is a prime.

It is a super-3 number, since 3×45010354021141³ (a number of 42 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (45010354021111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171795244225 + ... + 171795244486.

It is an arithmetic number, because the mean of its divisors is an integer number (11338486127496).

Almost surely, 2^{45010354021141} is an apocalyptic number.

It is an amenable number.

45010354021141 is a deficient number, since it is larger than the sum of its proper divisors (343590488843).

45010354021141 is a wasteful number, since it uses less digits than its factorization.

45010354021141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 343590488842.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 45010354021141 its reverse (14112045301054), we get a palindrome (59122399322195).

The spelling of 45010354021141 in words is "forty-five trillion, ten billion, three hundred fifty-four million, twenty-one thousand, one hundred forty-one".