Base | Representation |
---|---|
bin | 100000110001000111111… |
… | …1100011001011111001011 |
3 | 120221112102111100200000121 |
4 | 1001202033330121133023 |
5 | 1042241222404414011 |
6 | 13324521550444111 |
7 | 643240636230343 |
oct | 101421774313713 |
9 | 16845374320017 |
10 | 4503540701131 |
11 | 1486a3935624a |
12 | 608996803637 |
13 | 2688b3663824 |
14 | 117d888b7d23 |
15 | 7c232889e71 |
hex | 4188ff197cb |
4503540701131 has 2 divisors, whose sum is σ = 4503540701132. Its totient is φ = 4503540701130.
The previous prime is 4503540701129. The next prime is 4503540701227. The reversal of 4503540701131 is 1311070453054.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4503540701131 - 21 = 4503540701129 is a prime.
It is a super-2 number, since 2×45035407011312 (a number of 26 digits) contains 22 as substring.
Together with 4503540701129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4503540771131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2251770350565 + 2251770350566.
It is an arithmetic number, because the mean of its divisors is an integer number (2251770350566).
Almost surely, 24503540701131 is an apocalyptic number.
4503540701131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4503540701131 is an equidigital number, since it uses as much as digits as its factorization.
4503540701131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 4503540701131 in words is "four trillion, five hundred three billion, five hundred forty million, seven hundred one thousand, one hundred thirty-one".
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