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452125341503 = 1141102303773
BaseRepresentation
bin1101001010001001100…
…01010011011100111111
31121020000101121002001122
412211010301103130333
524401423041412003
6543411543101155
744444041664453
oct6450461233477
91536011532048
10452125341503
11164821a71a30
127375ba417bb
13338347cc694
1417c50c98663
15bb62b5e238
hex6944c5373f

452125341503 has 4 divisors (see below), whose sum is σ = 493227645288. Its totient is φ = 411023037720.

The previous prime is 452125341497. The next prime is 452125341523. The reversal of 452125341503 is 305143521254.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 452125341503 - 24 = 452125341487 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (452125341523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20551151876 + ... + 20551151897.

It is an arithmetic number, because the mean of its divisors is an integer number (123306911322).

Almost surely, 2452125341503 is an apocalyptic number.

452125341503 is a deficient number, since it is larger than the sum of its proper divisors (41102303785).

452125341503 is a wasteful number, since it uses less digits than its factorization.

452125341503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41102303784.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 452125341503 its reverse (305143521254), we get a palindrome (757268862757).

The spelling of 452125341503 in words is "four hundred fifty-two billion, one hundred twenty-five million, three hundred forty-one thousand, five hundred three".

Divisors: 1 11 41102303773 452125341503