470000000000023 has 2 divisors, whose sum is σ = 470000000000024. Its totient is φ = 470000000000022.

The previous prime is 469999999999991. The next prime is 470000000000039. The reversal of 470000000000023 is 320000000000074.

It is an a-pointer prime, because the next prime (470000000000039) can be obtained adding 470000000000023 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 470000000000023 - 2⁵ = 469999999999991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 469999999999898, 469999999999907 and 470000000000006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (470000000000623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 235000000000011 + 235000000000012.

It is an arithmetic number, because the mean of its divisors is an integer number (235000000000012).

Almost surely, 2^{470000000000023} is an apocalyptic number.

470000000000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

470000000000023 is an equidigital number, since it uses as much as digits as its factorization.

470000000000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168, while the sum is 16.

Adding to 470000000000023 its reverse (320000000000074), we get a palindrome (790000000000097).

The spelling of 470000000000023 in words is "four hundred seventy trillion, twenty-three", and thus it is an aban number.