Base | Representation |
---|---|
bin | 100010010011001000001… |
… | …1010111111101101111111 |
3 | 121200122122220122110201111 |
4 | 1010212100122333231333 |
5 | 1104213234020311201 |
6 | 14005325505222451 |
7 | 664401236613454 |
oct | 104462032775577 |
9 | 17618586573644 |
10 | 4714002119551 |
11 | 155821933699a |
12 | 641731931a27 |
13 | 2826b41371ca |
14 | 12423210d82b |
15 | 8294e463b51 |
hex | 449906bfb7f |
4714002119551 has 2 divisors, whose sum is σ = 4714002119552. Its totient is φ = 4714002119550.
The previous prime is 4714002119549. The next prime is 4714002119579. The reversal of 4714002119551 is 1559112004174.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4714002119551 - 21 = 4714002119549 is a prime.
Together with 4714002119549, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4714002119591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2357001059775 + 2357001059776.
It is an arithmetic number, because the mean of its divisors is an integer number (2357001059776).
Almost surely, 24714002119551 is an apocalyptic number.
4714002119551 is a deficient number, since it is larger than the sum of its proper divisors (1).
4714002119551 is an equidigital number, since it uses as much as digits as its factorization.
4714002119551 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 40.
The spelling of 4714002119551 in words is "four trillion, seven hundred fourteen billion, two million, one hundred nineteen thousand, five hundred fifty-one".
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